Use low voltage to control high voltage, have you seen this push-pull circuit?

Usually , with conventional push-pull output , 5V controls 12V, and the output result will be a square wave of 0.7V~4.3V.

 The advantage of the push-pull circuit below, compared to conventional push-pull output, is that it can use low voltage (5V) to control high voltage (12V).

How is it achieved?

 When the PWM output is high , there are two transistors, one will be cut off (Q2) and the other will be turned on (Q1). The MOS tube Cgs capacitor will be discharged quickly through the diode D1 and Q1.

 However, because Q1 is in the on state, the Vout voltage will quickly drop to Vce+Vd, and the Vgs capacitor of the MOS tube will be discharged quickly.

Here Vce is the saturation voltage drop of the transistor, and Vd is the forward conduction voltage drop of the diode.

When the PWM output is low , Q1 is cut off and Q2 is turned on. Q2 is equivalent to an emitter follower, charging the Cgs capacitor of the MOS tube. When the Cgs voltage is charged to 11.3V, the charging of the capacitor Cgs is completed.

 In general, when PWM is high, Vout output level is low, and the MOS tube is turned off. On the contrary, when PWM is low, Vout output level is high, and the MOS tube is turned on.

What do you think of this circuit? If you have better ideas, please leave a comment in the comment section!

Some of the above pictures and information are from the Internet